A ball is thrown horizontally from a height of 1 m and lands 5 m away. What is the time of flight of the ball?

The time of flight of the ball is approximately 0.4515 s

Explanation:

The given information are;

The vertical height, s = 1 m

The horizontal distance travelled, x = 5 m

The direction of the initial velocity = Horizontal

Given that the vertical height is known and the ball is in free fall, the time of flight, t, will depend on the vertical motion of the ball

The equation of motion of the ball can be presented as follows;

s = u·t + 1/2·g·t²

The initial vertical velocity = 0

∴ 1 = 1/2 × 9.81 × t²

t² = 1/(1/2 × 9.81 ) ≈ 0.20387 s²

t = √0.20387 = 0.4515 s

The time of flight of the ball ≈ 0.4515 s.

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