A trebuchet launches a pumpkin at an angle of 63 degrees at an initial velocity of 51 m/ s from the ground. What is the range of the pumpkin?

214.72m

Explanation:

The range (R) of a projectile can be calculated using the formula:

R = u²sin2θ/g

Where R = Horizontal range

u = initial velocity

θ = angle of initial velocity

g = acceleration due to gravity (9.8m/s²)

According to the provided information in this question, R= ?, u= 51m/s, θ = 63°, g = 9.8m/s².

Hence, R = u²sin2θ/g

R = 51² × sin 2×63/ 9.8

R = 2601 × sin 126/9.8

R = 2601 × 0.809/9.8

R = 2104.25/9.8

R = 214.72m

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.