Two friends push a stalled 1330 kg car with a 187 N force,
How much time does it take
to move the car 5.00 m?
(Unit = s)

8.42s

Explanation:

The time (in seconds) needed to move the car can be calculated using the formula:

S = ut + 1/2at²

Where; S = distance (m) = 5m

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

However, the acceleration (a) can be got by using F = ma

Where; F = force = 187 N

m = mass = 1330 kg

F = ma

a = F/m

a = 187/1330

a = 0.1406

a = 0.141m/s²

Since a= 0.141m/s², S = 5m, t =

S = ut + 1/2at²

5 = (0 × t) + 1/2 × (0.141 × t²)

5 = 0 + 0.141t²/2

5 = 0.141t²/2

10 = 0.141t²

t² = 10/0.141

t² = 70.922

t = √70.922

t = 8.42s

it would be kevlar ^^