Moments later, your friend passes the ball back up to you. Your friend throws it straight upwards at a speed of 16.6 m/s. If you catch it when it is still travelling upward at 5.3
m/s how far apart are you and your friend?

Analysing the question:

since the ball is thrown upwards, the gravity will be applied opposite to the motion of the ball

We are given:

acceleration due to gravity (a) = -10 m/s²

initial upward velocity (u) = 16.6 m/s

final upward velocity (v) = 5.3 m/s

distance between the friends (s) = s m

Neglecting air resistance

Solving for the distance between the friends:

from the first equation of motion

v = u + at

replacing the variables

5.3 = 16.6 + (-10)(t)

-10(t) = 5.2 - 16.6

-10 (t) = -11.3

t = 1.13 seconds

from the second equation of motion

s = ut + 1/2 at²

replacing the variables

s = (16.6)(1.13) + -5(1.13)²

s = 18.8 - 6.4

s = 12.4 m

Therefore, the 2 friends are 12.4 m apart

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia