Activity 3. Let's Do The Mathi Direction: Use Newton's second law equation to solve for force, mass, and acceleration
Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration?
Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface
with a force of 50N?
Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the
resulting acceleration of the object?
Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is
applied to it. What is the amount of the force?
Problem 5- An object accelerates 12.0 m/s2 when a force of 6.0 N is applied to it. What is the
mass of the object?

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3. m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3. m/s²

The acceleration = 3. m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

and 1and 1

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.