A Coast Guard cutter detects an unidentified ship at a distance of 21.0 km in the direction 15.0° east of north. The ship is traveling at 20.0 km/h on a course at 40.0° east of north. The Coast Guard wishes to send a speedboat to intercept and investigate the vessel. (a) If the speedboat travels at 58.0 km/h, in what direction should it head? Express the direction as a compass bearing with respect to due north.

(b) Find the time required for the cutter to intercept the ship.

initial speed Vi= 10.0 m/s in the horizontal direction. A cross ... which provide a constant horizontal acceleration of 15.0 m/s. ... A coast Guard cutter detects an unidentified ship at a distance of 20.0 km in the direction 15.0' east of north. The ship is travelling at 26.0 km/h on a course at 40° east of north

Explanation:

see earlier answer

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft