Physics, 18.10.2020 08:01 electrofy456

The first thing that I did was calculate the momentume of each shape before the collisions. To find the momentum
before the collision I used thew equation p=mv. Using
this equation I found the momentums for the triangle and
the circle. For the triangle the before momentum
was(2kg)(4m/s) = 8kgm/s and the circle was (6kg)(4m/
s) =24kgm/s. With those two shapes coliding I had to add
both of those numbers together and it would be 32kgm/s.
Next, I used the momentum equation (p=mv) to figure out
who's speed was found AFTER the collision which was
(32-24)= 8kgm/s. Since the momentum before was
32kgm/s. I subtracted the total by the circle before and
the circle after thr collision. Finally I usesd the
momentum equation, solved for v (p=m--> v=p/m) to
determine the velocity of the circle after the collision

-I want this re-worded but similar

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The first thing that I did was calculate the momentume of each shape before the collisions. To find...

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