A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, the center of mass of the bowling pin is moving upward with a speed vi of 10 The maximum height of the center of mass of the bowling pin is most nearly

Explanation:

In projectile, the formula for calculating the maximum height reached by the pin is expressed as;

H = u²/2g

u is the speed/velocity = 10m/s

g is the acceleration due to gravity = 9.81m/s²

Substitute

H = 10²/2(9.81)

H = 100/19.62

H = 5.097m

Hence the maximum height of the center of mass of the bowling pin is most nearly 5.0m

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s