A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?

8 m/s².

Explanation:

We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:

Mass (m) = 0.25 Kg

Acceleration (a) = 16 m/s²

Force (F) =.?

Force (F) = mass (m) × acceleration (a)

F = ma

F = 0.25 × 16

F = 4 N

Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.

Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:

Mass (m) = 0.50 Kg

Force (F) = 4 N

Acceleration (a) =?

F = ma

4 = 0.5 × a

Divide both side by 0.5

a = 4 / 0.5

a = 8 m/s²

Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

its c i just checked it