A curve that has a radius of is banked at an angle of . If a -kg car navigates the curve at without skidding, what is the minimum coefficient of static friction between the pavement and the tires

0.65

Explanation:

For whatever reasons, the parameters are not giving. So, I will assume by myself to make the calculations easier. You can substitute whatever it is to it from your question.

Given that

Radius of the road, r = 63 m

Speed of the car, v = 20 m/s

The relationship between a car that is passing through a curve and it's frictional force is said to be

U(s) * g = v²/r

In the formula above,

U(s) = coefficient of static friction

g = acceleration due to gravity, 9.8 m/s²

v = velocity of the car

r = radius of the road

Now when we substitute the earlier stated values, we have

U(s) * 9.8 = 20² / 63

U(s) * 9.8 = 400 / 63

U(s) * 9.8 = 6.35

U(s) = 6.35 / 9.8

U(s) = 0.65

Thus, our coefficient of static friction, based on the stated values is 0.65

you have to draw the persons position over there