Two protons are a distance 3 10-9 m apart. What is the electric potential energy of the system consisting of the two protons

The electric potential energy of the system is 7.87x10⁻²⁰ J.

Explanation:

The electric potential energy is given by:

Where:

q₁ = q₂ is the charge of the protons = 1.62x10⁻¹⁹ C

r is the distance = 3x10⁻⁹ m

K: is the electrostatic constant = 9x10⁹ Nm²/C²

Therefore, the electric potential energy of the system is 7.87x10⁻²⁰ J.

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