A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . What is the acceleration of the box?

The acceleration of the box is 0.67 m/s²

Explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

Where, F = horizontal force

=frictional force

m= mass of box

a = acceleration

Put the value into the formula

Hence, The acceleration of the box is 0.67 m/s²

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

i guess it’s a and b