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a student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 22 m/s at an angle= 31degrees below horizontal. the stone moves without air resistance; use a cartesian coordinate system with the origin at the stone's initial position.
50% part (a) with what speed, vf in meters per second, does the stone strike the ground?
50% part (b) if the stone had been thrown from the clifftop with the same initial speed and the same angle, but above the horizontal, would its impact velocity be different?

(i) v = 25.3 m/s

(ii) v = 25.3 m/s

Explanation:

Initial velocity of the stone is 22 m/s at an angle 31 degree

so here components of velocity in x and y direction is given as

now since there is no acceleration in x direction so horizontal velocity will remain constant always

While in y direction there exist gravity due to which velocity will be given as

now net speed of impact is given as

PART b)

Since the stone is thrown vertically upwards

So here components of velocity in x and y direction will be same as initial

Also the displacement in x and y direction is also same

So here final velocity of impact will not change and it will be same as we got in part a)

i think the answer would be reserve.