An archer shoots an arrow with vertical velocity of 10 m/s and horizontal velocity of 30m/s. What is the maximum height the arrow reaches?

5.1 m

Explanation:

Given in the y direction:

v₀ = 10 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (10 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 5.1 m

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer