A train leaves the station at the 0.0m marker traveling with a constant velocity of 45.0 m/s. How many seconds later will the train pass the 1500.Om marker? What is the velocity of the train in km/h?

33.3 s

162 km/h

Explanation:

Given:

Δx = 1500.0 m

v₀ = 45.0 m/s

a = 0 m/s²

Find: t

Δx = v₀ t + ½ at²

1500.0 m = (45.0 m/s) t + ½ (0 m/s²) t²

t = 33.3 s

Convert m/s to km/h:

45.0 m/s × (1 km / 1000 m) × (3600 s / 1 hr) = 162 km/h

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