Determin the acceleration that results when an object starts at rest moves a distance and it’s final speed is 49 m/sec (show work please and equation used)
(also don’t understand this question at all)

The answer is below

Explanation:

The question is not complete since the distance is not given. But let us assume the object moves a distance of 100 m.

From newton's law for a moving body, we get the equation:

v² = u² + 2as

Where v is the final velocity of the object, u is the initial velocity of the object, s is the distance moved by the object and a is the acceleration of the object.

Given that the object is initially at rest, hence u = 0, final speed (v) = 49 m/s, distance (s) = ?

v² = u² + 2as

Substituting:

49² = 0² + 2as

2401 = 2as

a = 2401 / 2s

Substituting s = 100 m

a = 2401 / (2*100)

a = 12 m/s²

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation:

photocells convert light energy to electricity