A ball is dropped from the top of a building and hits the street below in 4.25 s. How tall is the building? Show work for brainliest.

90.3125 m

Explanation:

a = 10m/s^2 (constant)

S=height

U=initial velocity

a= gravitational acceleration

t= time

s = 0 + 1/2 * 10 * 4.25 ^2

u is 0 because it is dropped without velocity

s =90.3125 m

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg