The lower the angle of the slope, the acceleration along the ramp, therefore, the speed at the bottom of a slope will be, and, consequently, the control will be better. The acceleration along the ramp, therefore, the speed at the bottom of a slope will be:
a. lower
b. gcostheta
c. higher
d. gsintheta

Lower

Lower

gsintheta (gsinθ)

Explanation:

The sum of forces resolved parallel to the inclined plane is given by;

F - mgsinθ = 0

ma - mgsinθ = 0

ma = mgsinθ

a = gsinθ

Acceleration is proportional to angle of inclination, thus the lower the angle of the slope, lower the acceleration along the ramp.

therefore, the speed at the bottom of a slope will be lower, (velocity is directly proportional to acceleration) and, consequently, the control will be better.

The acceleration along the ramp, is gsintheta (gsinθ)

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

490 n

f=125n a=2.5m/s2