2. Kymel is competing to see who is the fastest runner on the football team. Kymel uns from rest to a speed of 4 m/s when he reaches the 20 meter mark in just 2 minutes.
What was Kymel's acceleration during the run?
a. 2 m/s2
b. 30 m/s2
c. 0.5 m/s2
d. 0.03 m/s2
PsX

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Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

The answer is trial 3.