A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 m/s (due to inertia) until something solid like the steering wheel is encountered. The driver now comes to rest in a much shorter distance-perhaps only a few centimeters. Find the magnitude of the net force acting on a 65.0 kg driver who is decelerated from 18.0 m/s to rest in 5.00 cm. A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 (due to inertia) until something solid like the steering wheel is encountered. The driver now comes to rest in a much shorter distance-perhaps only a few centimeters. Find the magnitude of the net force acting on a 65.0 driver who is decelerated from 18.0 to rest in 5.00 . F=3240N F=1.173×104N F=2.113×105N F=4.213×105N

F = 2.113 x 10⁵ N

Explanation:

First we need to calculate the deceleration of the driver by using 3rd equation of motion:

2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance = 5 cm = 0.05 m

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 18 m/s

Therefore,

2a(0.05 m) = (0 m/s)² - (18 m/s)²

a = (- 324 m²/s²)/0.1 m

a = - 3240 m/s²

where, negative sign represents deceleration

From Newton's Second Law of Motion:

F = ma

F = (65 kg)(-3240 m/s²)

F = - 2.106 x 10⁵ N

So, he closest answer is:

F = 2.113 x 10⁵ N

explanation:

newton's third law, for every action there is an equal and opposite reaction.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min