One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separated by 0.015 m, what is the electromagnetic force between them? A. 4.31 x 10^ -7 N B. 2.77 x 10^ -4 N C. 4.15 x 10^ -6 N D. 6.22 x 10^ -4 N

B. 2.77 x N

Explanation:

The required force can be calculated by:

F =

Where F is the force between the particles, K is the coulomb's constant (9 x ), is the charge on the first particle, is the charge on the second particle and is the distance between the particles.

So that:

F =

  =

  = 2.7692 x

 The force between the particles is 2.77 x N.

are there options? cause you ain’t. real specific

pe = weightxheight = 2000x1000=2,000,000joules