Sand moves without slipping at 6.0 m/s down a conveyer that is tilted at 15∘. The sand enters a pipe h = 2.7 m below the end of the conveyer belt, as shown in the figure (Figure 1). What is the horizontal distance d between the conveyer belt and the pipe?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

that the claims meet official rules.

don't misinterpret the claims

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//