A student is experimenting with two sets of balls colliding in a closed system. In the first trial, two hard balls collide for 0.01 seconds.

In the second trial, two softer balls collide for 0.02 seconds.

The amount of force applied to each set of balls is equal.

Which statement is correct about these trials?

The momentum in the first trial is half the impulse in the second trial.

The impulse in the first trial is half the impulse in the second trial.

The momentum in the first trial is twice the impulse in the second trial.

The impulse in the first trial is twice the impulse in the second trial.

A

The momentum in the first trial is half the impulse in the second trial

Explanation:

Given that a student is experimenting with two sets of balls colliding in a closed system. In the first trial, two hard balls collide for 0.01 seconds.

In the second trial, two softer balls collide for 0.02 seconds.

The amount of force applied to each set of balls is equal.

Impulse = product of force and time.

While

Momentum = product of mass and velocity.

Impulse = momentum.

Since the force applied to the two balls are the same.

The impulse for the first experiment = 0.01F

The impulse for the second experiment = 0.02F

We can therefore conclude that: The momentum in the first trial is half the impulse in the second trial

car a and b are moving in opposite directions

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weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards