Fast ball with a velocity of 43 m/s south. The batter hits the ball and gives it a velocity of 51 m/s north. What was the acceleration of the ball if it was in contact with the bat for 1 s? What direction did it go? PLEASE HELP I NEED THIS DONE FOR MY NEXT CLASS

Acceleration = (change in velocity) / (time for the change)

change in velocity = (velocity after) - (velocity before)

change in velocity = (51 m/s north) - (43 m/s south)

that's the same thing as (51 m/s north) + (43 m/s north)

change in velocity = 94 m/s north

Acceleration = (94 m/s north) / (1 second)

Acceleration = 94 m/s² north

The direction of the acceleration is North.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)