A biker with an initial velocity of 16.0 m/s slows uniformly to 6.0 m/s in 8.0 seconds. What is the acceleration of the car during this 8.0-second interval?

-1.25 m/s²

Explanation:

Given:

v₀ = 16.0 m/s

v = 6.0 m/s

t = 8.0 s

Find: a

v = at + v₀

6.0 m/s = a (8.0 s) + 16.0 m/s

a = -1.25 m/s²

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explanation:

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