Compare the minimum energies required to remove a neutron from Ca, zzCa and 23Ca, using m40=37225.15 MeV/c2, m41=38156.36 MeV/c?, m42=39084.46 MeV/c?, m43=40016.10 MeV/c and mn=939.57 MeV/c2. Why there is a distinct increase of this energy for Ca?

Explanation:

From the given information, we are to compare the minimum energies required to remove a neutron from  ,    and  

To start with   ; the minimum  energy required to remove a neutron from is :

=

= (38156.36 - 37225.15 -939.57) MeV

= -8.36 MeV   Since energy is being given out

Thus, E = 8.36 MeV

the minimum  energy required to remove a neutron from is :

=

= ( 39084.46 - 38156.36 - 939.57) MeV

= -11.47 MeV     Since energy is being given out

Thus, E = 11.47 MeV  

the minimum  energy required to remove a neutron from is :

=

= (40016.10 -39084.46 -939.57) MeV

=  - 7.93 MeV     Since energy is being given out

Thus, E =7.93  MeV

Why there is a distinct increase of this energy for ?

This is as a result of electronic configuration of which posses the same number of proton and neutron, as such, tends to acquire more stability. For this reason, it will be difficult to remove a neutron from .

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: