Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a higher potential than the outer surface. A potassium ion (K+) is initially just outside the cell membrane (initially at rest). How much work (in J) is required for a cell to absorb the ion, so that it moves from the exterior of the cell to the interior?

W = J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = C

To determine work in joules, potential has to be in Volts, so:

Then, work is

To move a potassium ion from the exterior to the interior of the cell, it is required J of energy.

what is the actual question though?

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.