The mercury manometer of fig. P2.57 indicates a differential reading of 0.30 m when the pressure in pipe a is 30-mm hg vacuum. Determine the pressure in pipe b.

The pressure in pipe b is 33.4 kpa.

Explanation:

Given that,

Pressure in pipe a = 30 mm hg vacuum

Differential reading = 0.30 m

We need to calculate the pressure in pipe b

Using diagram

Where, P = pressure

W= specific weight

Put the value into the formula

Put the value of specific weight

Hence, The pressure in pipe b is 33.4 kpa.

answer; /// i believe that the correct answer is (c)

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//