PLEASE HELP! What is the magnitude of the instantaneous velocity (speed) of a freely falling object 32s after it is released from a position of rest? Consider the acceleration of gravity to be 10 m/s^2 Answer in units of m/s. What is its average speed during this 32 s interval? Answer in units of m/s. How far will it fall during this time? Answer in units of m.

The earths atmosphere is made up of nitrogen and oxygensolids turning into gases is called sublimation.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Ithink c because you have to work to become goid