A man walks 2km in 1.5min, how many time need to walk 6.9km

t = 5.2 min

Explanation:

given:

A man walks 2km in 1.5min,

find:

how many time need to walk 6.9km

solution:

its a ratio and proportion

    2 km  x    6.9 km

  1.5 min            t

then cross multiply:

2 (t) = 6.9 ( 1.5)

t = 10.35 / 2

t = 5.2 min

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j