What is the acceleration of a 1.5 kg football thrown with a force of 13.00 N to the east with a westward wind opposing it with a force of 4.000 N?

The acceleration of football is 6.00 m/s².

Explanation:

The acceleration can be calculated using the following equation:

Where:

F: is the force

m: is the mass

a: is the acceleration

Therefore, the acceleration of football is 6.00 m/s².

I hope it helps you!

2b2t

explanation:

2b2t

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west