A lunar module weighs 12 tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moon to a height of 60 miles? Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth.

Work done = 1716560.9 Joule

Explanation:

Given that a lunar module weighs 12 tons on the surface of the Earth.

How much work is done in propelling the module from the surface of the moon to a height of 60 miles?

Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth.

1 ton = 907.185 kg

12 tons = 10886.22 kg

1 mile = 1.609 km

60 miles = 96.54 km

1100 miles = 1.609 × 1100 = 1769.9 km

Since it is from the surface of the moon, the work done = mgh

WD = 10886.22 × 9.8/6 × 96.54

WD = 1716560.9 J