ball is thrown vertically upward from an initial position 5m above the ground. At the same time, a cube is released from rest down aslippery incline, from an unknownheight. The two objects reach the ground at the same instant, and both have a final speed of 15m/s. What is the angle ofthe incline

The value is

Explanation:

Generally the time it takes the ball to move from maximum height to the ground is

Here u= 0 m/s and v = 15 m/s

So

=>

Generally the maximum height traveled in time t is mathematically represented as

=>

=>

The interval in distance between the maximum height and the initial position of the ball is

Here k = 5 m (given)

Generally from the kinematic equation we have that

Here is the time taken to travel through d

=>

=>

Generally the total time for this fight is mathematically represented as

=>

=>

Generally the vertical force exerted on the cube is mathematically represented as

=>

=>

Now a is mathematically represented as

=>

=>

So

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr