Two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N . If a charge of -5 micro coulomb is added to each of them, then the force between them will become?

1 N

Explanation:

Given that two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N.

Let us first calculate the distance between the two point charges

F = (KQq)/r^2

Where K = 9.0 × 10^9Nm^2C^-2

40 = (9×10^9 × 3×10^-6 × 8×10^-6)/r^2

Make r^2 the subject of formula

r^2 = 0.216/40

r = sqrt (5.4^-3)

r = 0.0735 metres

If a charge of -5 micro coulomb is added to each of them, then the force between them will become?

Using the same formula again

F = ( KQq)/r^2

Where Q = 8 - 5 = +3 × 10^-6 C

q = 3 - 5 = - 2 × 10^-6 C

F = ( 9×10^9 × 3×10^-6 × 2×10^-6 )/5.4×10^-2

F = 0.054/0.054

F = 1 N

The force of attraction between the two point charges will be 1 N

whichever one it is, it's definitely not one that you included on the list you provided.

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!