A car, initially traveling 24.0ft/s, steadily speeds up to 58.0ft/s in 5.40s. Determine all unknowns and answer the following question. How far did the car travel during this time?

acceleration = 6.29 ft^2/s

distance traveled by car = 405 ft

Explanation:

formula 1 : u = v - (a*t)

where u = initial velocity

v = final velocity

a = acceleration

t = time.

solving for acceleration.

24 = 58 - (a*5.4)

a = (58 - 24)/ 5.4

a = 340/ 54 = 6.29 ft^2/s

formula 2: v = d/t - (a*t/2)

58 = d/5.4 - ((340*54)/20)

d = 405 ft

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