The volume (in l) that would be occupied by 5.00 mol of o2 at stp is
a. 0.411 l.
b. 22.4 l.
c. 41.6 l.
d. 112 l.

At STP, temperature is 273.15 K and the pressure is at 1 atm. The volume occupied by the system given above can be calculated by using the ideals gas equation assuming that O2 is an ideal gas.

PV = nRT
V = nRT / P
V = 5.00 mol (0.08206 L atm / mol K ) (273.15) / 1 atm
V = 112 L

Therefore, the correct answer is option D.