Holes are being steadily injected into a region of n-type silicon (connected to other devices, the details of which are not important for this question). In the steady state, the excess-hole concentration profile shown in fig. P3.10 is established in the n-type silicon region. Here "excess" means over and above the thermal-equilibrium concentration (in the absence of hole injection), denoted pn0. If nd = 1016/cm3, ni =1.5×1010/cm3, dp =12 cm2/s, and w =50 nm, find the density of the current that will flow in the x direction.

Complete Question

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The  value  is  

Explanation:

Generally for an n-type semiconductor the current density is mathematically represented  as

Here   is mathematically represented as

=>      

=>      

So

From the diagram  

=>  

So

So  from  

substitute

    for  q  and  

and from the diagram  

So

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explanation:

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