What is the wavelength of electromagnetic radiation needed to eject 3.0 ev?

4.125 × 10^-7m

Explanation:

The formula for calculating the energy level of electron is expressed as;

∆E = hf

h is the Planck's constant

f is the frequency

f = velocity of light/wavelength

f = c/λ

c is the velocity of light

λ is the wavelength

∆E = hc/λ

Given ∆E = 3.0eV

Since 1eV = 1.6×10^-19Joules

∆E = 3×1.6×10^-19Joules

∆E = 4.8×10^-19Joules

Other given parameters

c = 3×10^8m/s

h = 6.6×10^-34Js

From the formula ∆E = hc/λ

λ = hc/∆E

λ = 6.6×10^-34 × 3×10^8/4.8×10^-19

λ = 19.8×10^{-34+8}/4.8×10^-19

λ = 19.8×10^-26/4.8×10^-19

λ = 19.8/4.8 × 10^{-26-(-19)}

λ = 19.8/4.8 × 10^{-26+19}

λ = 4.125 × 10^-7m

Hence the wavelength of the electromagnetic radiation is 4.125 × 10^-7m

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.