During the flight of the ball to the wicket-keeper, the horizontal velocity remains unchanged. The speed of the ball at the moment the wicket-keeper catches it is 19 m/s
,

calculate for the ball just as it is caught:

i) Its vertical speed,

ii) The angle that the path of the ball makes with the horizontal.

iii) Suggest with a reason whether the ball, at the moment it is caught, if it is rising or

falling?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Well the magnitude of its acceleration related to that car starts with the oil change like when you have to change the oil in your car you have to make sure that your precious car is starting really propley and very well