What was the average speed for the second leg of the trip? help me im stuck

The average speed on the second leg of the trip is 2 m/s

Explanation:

Notice that the second leg of the trip is from 8 m in the horizontal axis heading to the left to position 4 m. So the velocity is going to be negative and given by the quotient of the change in position (-4 m) divided by the time it took: 2 seconds.

This gives: -4/ 2 m/s = -2 m/s

But the speed is going to be the absolute value of the velocity, that is:

2 m/s

+15-35=-20

going in opposite directions