A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is its final position? Answer please

1900 metres

Explanation:

Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.

The parameters to be considered are:

Speed = 30 m/s

Time = 30 seconds

Speed = distance/time

Substitute the parameters into the formula

30 = distance / 30

Cross multiply

Distance = 30 × 30

Distance = 900 m

Since the train started from a position of 1000 m , the final position will be:

Final position = 1000 + 900

Final position = 1900 metres

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answer:

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