Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s m / s . Once free of this area, it speeds up to 14 m/s m / s in 8.0 s s . At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s s to reach a higher cruising speed. What is the final speed? Express your answer to two significant figures and include the appropriate units.

30 m/s

Explanation:

We can equation of motion to solve this question.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.