Bacteria vary somewhat in size, but a diameter of 2.3 m is not unusual. A. What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical?Express your answer using two significant figures. B. What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?

a) 6.4 x 10^-12 cm^3

b) 17 x 10^-6 mm^2

Explanation:

The complete question is...

Bacteria vary somewhat in size, but a diameter of 2.3 m is not unusual.

A. What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical? Express your answer using two significant figures.

B. What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?

Diameter of the bacteria d = 2.3 μm

Radius r = d/2 = 2.3/2 = 1.15 μm

The shape is assumed to be spherical

a) The volume = volume of a sphere =

V = = 6.3715 μm^3

1 μm^3 = 10^-12 cm^3

6.3715 μm^3 = 6.3715 x 10^-12 cm^3

==> 6.4 x 10^-12 cm^3

b) The surface area =

A = 4 x 3.142 x = 16.62 μm^2

1 μm^2 = 10^-6 cm^2

16.62 μm^2 = 16.62 x 10^-6 mm^2

==> 17 x 10^-6 mm^2

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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