A cliff jumper jumps off a cliff with an initial horizontal velocity of 10 m/s. The cliff is 10 meters high. How far from the base of the cliff does the diamond fall?

The distance reached is 14.3 m.

Explanation:

To find the distance reached by the diamond first we need to find the flight time:

Where:

h: is the height = 10m

g: si the gravity = 9.81 m/s²

Now, we can find the distance reached:

Where:

is the initial horizontal velocity = 10 m/s

Therefore, the distance reached is 14.3 m.

I hope it helps you!