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Physics, 02.09.2020 06:01 jennyrr9021

Two students walk in the same direction along a straight path at a constant speed. - Student A walks at 0.90 m/s - Student B walks at 1.90 m/s Given this, what is the distance in which student B arrives 330 seconds faster than student A? Use the formula to solve the question: AVERAGE SPEED = DISTANCE TRAVELED / TIME OF TRAVEL

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Two students walk in the same direction along a straight path at a constant speed. - Student A walks...
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