A baseball is thrown horizontally at 46 m/s. The ball slows down at a rate of 5 m/s2. How long is the ball in the air before coming to rest?

Explanation:

Using one of the equation of motion v = u + at where;

v is the final velocity = 0m/s (the ball comes to rest after throw)

u is the initial velocity = 46m/s

a is the acceleration = -5m/s² (the body decelerates)

t is the time taken by the ball in air

substituting the given parameters into the formula to get t, we will have;

0 = 46 +(-5)t

0 = 46 - 5t

subtract 46 from both sides

0-46 = 46-5t-46

-46 = -5t

Divide both sides by -5

-46/-5 = -5t/-5

t = 46/5

t = 9.2seconds

Hence it will take the ball 9.2seconds in the air before coming to rest.

correct it is c.) b b

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =