A woman exerts a horizontal force of 5 pounds on a box as she pushes it up a ramp that is 6 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.

26 lbft

Explanation:

Given that

Force exerted by the woman, F = 5 lb

Length of the ramp, d = 6 ft

angle of inclination, θ = 30° above the horizontal

Work done on the box, W = ?

This is very much a straightforward question..

Work done, W = F * d, where the force takes the factor of the Angie if inclination. So that,

W = Fcosθ * d

On substituting, we have

W = 5 * cos 30 * 6

W = 5 * 0.866 * 6

W = 30 * 0.866

W = 25.98 lbft

Therefore, the work done on the box is 25.98 or approximately 26 lbft

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