A child of mass 22.0 kg is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force must she experience to stay on if she is 1.25 m from the center

Centripetal Force = 483.3 N

Explanation:

A centripetal force is the force that tends to keep a mocing object along a curved path and it is directed towards the centre of the rotatio, while centrifugal force is an apparent force that tends to force a rotating object away from the center of the rotation.

The formula for centripetal force is given by:

Let us work on the angular velocity (ω), by converting to radians/ seconds

ω = 40 rev/min,

1 rev = 2π rad

∴ 40 rev = 2π × 40 rad = 80π rad

1 min = 60 seconds

Next let us find the velocity (v) from the angular velocity. Velocity (v) and angulsr velocity (ω) are related by the equation:

v = ω × r (m/s)

v = 4.189 × 1.25

v = 5.24 m/s

Finally, the centripetal force is calculated thus:

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.