CRITICAL THINKING In the diagram below the area of the small piston is 2m² and the large piston is 120 m².
piston
piston
liquid under pressure
a. If the small piston is pushed down with a force of 20N, calculate the pressure exerted
on the liquid
b. If the same pressure is transmitted by the liquid to act on the large piston, calculate
the force acting on the large piston.
Compare the force acting on the large piston with that being exerted on the smaller piston.
IT OTTOTY

a. pressure of the liquid

pressure = force over area

pressure = F/A

pressure = 20N/2m2

pressure = 10pascals

b force of small piston over area of small piston equalling to force of large piston over area of large piston

now let the unknown force of large piston be x

f/a = F/A

20/2 = x/120

we cross multiply

20×120 = 2×x

2400 = 2x

we divide both sides by 2

2400/2 = 2x/2

1200 = x

the force of large piston is 1200N

i think its

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explanation: