A large tanker truck carrying Blazblue extract has a capacity of 29053 liters. The density of Blazblue extract is 0.770 grams per milliliter. What is the weight, in pounds, of a full load of Blyzblah extract.

1319.14 lb

Explanation:

From the question above,

Density of the Blazblue extract = mass of Blazblue extract/volume of Blazblue extract.

D = m/v Equation 1

make m the subject of the equation

m = D×v Equation 2

Given: D = 0.770 grams per millilitre, v = 29053 liters = 29053000 millilitres

Substitute these values into equation 2

m = 0.770×29053000

m = 22370810 grams

If,

1 gram = 0.00220462 pounds,

Then,

22370810 grams = (22370810×0.00220462) = 41319.14 lb

specific latent heat of fusion, lf, of a substance is defined as the amount of heat required to change a unit mass of the substance from solid to liquid state, without any change in the temperature.

explanation:

answer: good job it's all correct !

explanation: